In a series circuit with resistors R1 = 8 Ω, R2 = 11 Ω, and R3 = 13 Ω, which statement is true?

In a series circuit, the total voltage provided by the source is divided among the resistors according to their resistance values. The voltage drop across each resistor can be calculated using Ohm's Law, which states that the voltage ( V ) across a resistor is equal to the product of the current ( I ) flowing through it and its resistance ( R ) (i.e., ( V = I \cdot R )).

In this context, the current flowing through all resistors in a series circuit is the same. Therefore, the voltage drop across each resistor depends directly on its resistance value: the greater the resistance, the larger the voltage drop across that resistor.

For the given resistors, R1 is 8 Ω, R2 is 11 Ω, and R3 is 13 Ω. Among these, R3 has the highest resistance. Consequently, since the same current flows through all resistors, the voltage drop across R3 will be the greatest compared to R1 and R2. This means that resistance plays a critical role in determining where the most significant voltage drop occurs in the circuit.

This understanding of voltage drop in series circuits demonstrates why the statement about R3 having the greatest voltage drop is valid.