In a series circuit with a 240-volt source and three resistors of 8 ohms, 10 ohms, and 12 ohms, what is the current flow?

To determine the current flow in a series circuit with a 240-volt source and three resistors of 8 ohms, 10 ohms, and 12 ohms, one must first calculate the total resistance in the circuit. In a series circuit, the total resistance is simply the sum of the individual resistances.

In this case, the total resistance can be calculated as follows:

Total Resistance = 8 ohms + 10 ohms + 12 ohms = 30 ohms.

Next, to find the current flowing through the circuit, Ohm's Law is applied, which states that Voltage (V) = Current (I) × Resistance (R). Rearranging this formula to solve for current gives us:

Current (I) = Voltage (V) / Resistance (R).

Now, substituting the known values:

Current (I) = 240 volts / 30 ohms = 8 A.

The calculated current of 8 A is thus the flow of current in the circuit. This understanding of combining resistances in series circuits and applying Ohm's Law correctly leads to the conclusion of 8 A being the right answer for the current flow in this scenario.